How would I pass a Python variable to the Bash shell? It should work like this:
Replace the double-quotes with `s
I have tried printing and sys.exiting the result, but to no avail. How would I accomplish my goal?
call external program in python, watch output for specific text then take action
1:Valgrind 'noise', what does it mean?
That's it. How to send a EML file as email using python script to list of emails one at a time?
sys.stdout.write(). Displaying an image from the tmp directoryOr the like. How do they read clusters/cylinders/sectors from the disk?If the script isn't executable then you'll need to specify the interpreter explicitly.. Use OpenBSD's malloc, realloc and free in my program
foo="$(python scriptthatprintsany thing.py)"
Your desired form works just fine:.
so presumably the ways in which you had tried printing were incorrect. (This is quite independent from using the older-style backquotes, or newer-style constructs such as
$ cat >Retvar.py #!/usr/bin/python import sys print sys.argv $ chmod +x RetVar.py $ foo=`./RetVar.py 42` $ echo $foo 42 $
$()). If you still have this problem, must you show us the minimal case of Python code this reproduces it, to guidance us guidance you?.
In bash both
`cmd` and $(cmd) will be replaced by the output of the command. This allows you to assign the output of a program to a variable like .
Normally you wrap this in double quotes so you must have spaces in your output. It need be double quotes as stuff inside single quotes will not be executed. .